BackJoon Algorithm 토마토 7576 (Java)

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1 분 소요

BackJoon Algorithm - Java

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문제

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풀이

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.util.LinkedList;
import java.util.Queue;
import java.util.StringTokenizer;

public class Back_7576 {

    static int[] dx = {-1, 1, 0, 0};
    static int[] dy = {0, 0, -1, 1};

    static int n, m;
    static int[][] map;

    static Queue<int[]> q = new LinkedList<>();

    public static void main(String[] args) throws IOException {
        BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
        StringTokenizer st = new StringTokenizer(br.readLine());

        n = Integer.parseInt(st.nextToken());
        m = Integer.parseInt(st.nextToken());

        map = new int[m][n];
        for (int i = 0; i < m; i++) {
            st = new StringTokenizer(br.readLine());
            for (int j = 0; j < n; j++) {
                map[i][j] = Integer.parseInt(st.nextToken());
                if (map[i][j] == 1) {
                    q.add(new int[]{i, j});
                }
            }
        }
        System.out.println(bfs());
    }

    private static int bfs() {
        while (!q.isEmpty()) {
            int[] tomato = q.poll();
            int x = tomato[1];
            int y = tomato[0];
            for (int i = 0; i < 4; i++) {
                int nx = x + dx[i];
                int ny = y + dy[i];
                if (nx < 0 || nx >= n || ny < 0 || ny >= m) continue;
                if (map[ny][nx] == 0) {
                    map[ny][nx] = map[y][x] + 1;
                    q.add(new int[]{ny, nx});
                }
            }
        }

        int max = 0;
        if (checkZero()) {
            return -1;
        } else {
            for (int i = 0; i < m; i++) {
                for (int j = 0; j < n; j++) {
                    if(max < map[i][j]){
                        max = map[i][j];
                    }
                }
            }
            return max - 1;
        }
    }

    private static boolean checkZero() {
        for (int i = 0; i < m; i++) {
            for (int j = 0; j < n; j++) {
                if (map[i][j] == 0) {
                    return true;
                }
            }
        }
        return false;
    }
}


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